1/2m^2=1/m-1/2

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Solution for 1/2m^2=1/m-1/2 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(1/2)*m^2 = 1/m-(1/2) // - 1/m-(1/2)

(1/2)*m^2-(1/m)+1/2 = 0

(1/2)*m^2-m^-1+1/2 = 0

1/2*m^2-1*m^-1+1/2*m^0 = 0

(1/2*m^3+1/2*m^1-1*m^0)/(m^1) = 0 // * m^2

m^1*(1/2*m^3+1/2*m^1-1*m^0) = 0

m^1

(1/2)*m^3+(1/2)*m-1 = 0

(1/2)*m^3+(1/2)*m-1 = 0 // * 0

{ 1, -1, 2, -2 }

1

m = 1

m^3+m-2 = 0

1

m-1

m^2+m+2

m^3+m-2

m-1

m^2-m^3

m^2+m-2

m-m^2

2*m-2

2-2*m

0

m^2+m+2 = 0

DELTA = 1^2-(1*2*4)

DELTA = -7

DELTA < 0

m in { 1} 

m = 1

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